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[SOLVED]Question & Answer: Historical demand for a product is: a. Using a weighted moving average with weights of 0.40…..

Author: Client Uploads
February 16th, 2022

Historical demand for a product is DEMAND 13 February 13 15 a. Using a weighted moving average with weights of 040 (June), 020 (May), and 0.40 (April). find the July forecast. (Round your answer to 1 decimal place.) July forecast b. Using a simple three-month moving average. find the July forecast. (Round your answer to 1 decimal place.) July forecast c. Using single exponential smoothing with α : 0.20 and a June forecast : 12 find the July forecast. Round your answer to l decimal place. July forecast d. Using simple linear regression analysis, calculate the regression equation for the preceding demand data. (Do not round intermediate calculations. Round your intercept value to 1 decimal place and slope value to 2 decimal places.) e. Using the regression equation in d, calculate the forecast for July. (Do not round intermediate calculations. Round your answer to 1 decimal place.) July forecast

Historical demand for a product is: a. Using a weighted moving average with weights of 0.40 (June), 0.20 (May), and 0.40 (April), find the July forecast. (Round your answer to 1 decimal place.) July forecast b. Using a simple three-month moving average, find the July forecast. (Round your answer to 1 decimal place.) July forecast c. Using single exponential smoothing with alpha = 0.20 and a June forecast = 12, find the July forecast. (Round your answer to 1 decimal place.) July forecast d. Using simple linear regression analysis, calculate the regression equation for the preceding demand data. (Do not round intermediate calculations. Round your intercept value to 1 decimal place and slope value to 2 decimal places.) Y = + t e. Using the regression equation in d, calculate the forecast for July. (Do not round intermediate calculations. Round your answer to 1 decimal place.) July forecast

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Expert Answer

Answer:- Weighted moving average ;

Forecast for July = (14*0.4 + 15*0.2+13*0.4)/(0.4+0.2+0.4) = (5.6+3+5.2)/1

Forecast for July =13.8

Answer:- Simple three-month moving average:-

Forecast for July =(14+15+13)/2=14

Answer:-

Month Demand
Jan 13
Feb 10
March 14
April 13
May 15
June 14
Month (X) Number of Accident(Y) X*Y X*X
1 13 13 1
2 10 20 4
3 14 42 9
4 13 52 16
5 15 75 25
6 14 84 36
∑X = 21 ∑Y = 79 ∑XY = 286 ∑X^2 =91
Slope(b) = (N∑XY – (∑X)(∑Y)) / (N∑X2 – (∑X)2)
Slope B = (6*286 – 21*79)/(6*91-21^2)
B = 0.543
Intercept(a) = (∑Y – b(∑X)) / N
a=(79-0.543*21)/6
a=11.27
Regression Equation(y) = a + bx
y=11.27+0.543*x
Forecast for July
y=11.27+0.543*7
y=15.071

Related: regression analysis

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