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Home>Mathematics homework help>Numerical analysis homework help Chapter 4, Section 3, Exercise 075 Match the p-values with the appropriate conclusion: (a) The evidence against the null hypothesis is significant, but only at the 10% level. (b) The evidence against the null and in favor of the alternative is very strong. (c) There is not enough evidence to reject the null hypothesis, even at the 10% level. (d) The result is significant at a 5% level but not at a 1% level. Chapter 4, Section 3, Exercise 082 Sleep or Caffeine for Memory? The consumption of caffeine to benefit alertness is a common activity practiced by 90% of adults in North America. Often caffeine is used in order to replace the need for sleep. One recent study1 compares students ability to recall memorized information after either the consumption of caffeine or a brief sleep. A random sample of 35 adults (between the ages of 18-39 ) were randomly divided into three groups and verbally given a list of 24 words to memorize. During a break, one of the groups takes a nap for an hour and a half, another group is kept awake and then given a caffeine pill an hour prior to testing, and the third group is given a placebo. The response variable of interest is the number of words participants are able to recall following the break. The summary statistics for the three groups are in the table below. We are interested in testing whether there is evidence of a difference in average recall ability between any two of the treatments. Thus we have three possible tests between different pairs of groups: Sleep vs Caffeine, Sleep vs Placebo, and Caffeine vs Placebo. Group Sample size Mean Standard Deviation Sleep 12 15.25 3.3 Caffeine 12 12.25 3.5 Placebo 11 13.70 3.0 1 Mednick, Cai, Kanady, and Drummond, Comparing the benefits of caffeine, naps and placebo on verbal, motor and perceptual memory, Behavioural Brain Research, 193 (2008), 79-86. Warning H0. In the sample , which group had better recall ability? According to the test results, do you think sleep is really better than caffeine for recall ability? Warning H0. What is the conclusion of the test, if we use a 10% significance level? H0. How strong is the evidence of a difference in mean recall ability between these two treatments? Warning H0. In the sample , which group had better recall ability? According to the test results, would we be justified in concluding that caffeine impairs recall ability? Warning H0 Significance level: Group with the larger mean: (b) 99% confidence interval for m1-m2: -2.5 to 5.5 Conclusion:H0 Significance level: Group with the larger mean: (c) 90% confidence interval for m1-m2: -10.8 to -3.3 Conclusion:H0 Significance level: Group with the larger mean: Chapter 4, Section 5, Exercise 156 Are you In a Relationship? A new study1 shows that relationship status on Facebook matters to couples. The study included 58college-age heterosexual couples who had been in a relationship for an average of 19 months. In 45 of the 58 couples, both partners reported being in a relationship on Facebook. In 31 of the 58 couples, both partners showed their dating partner in their Facebook profile picture. Men were somewhat more likely to include their partner in the picture than vice versa. However, the study states: Females indication that they are in a relationship was not as important to their male partners compared with how females felt about male partners indicating they are in a relationship. Using a population of college-age heterosexual couples who have been in a relationhip for an average of 19 months: (a) A 95% confidence interval for the proportion with both partners reporting being in a relationship on Facebook is about 0.66 to 0.88. What is the conclusion in a hypothesis test to see if the proportion is different from 0.5? What significance level is being used? Conclusion: H0 Significance level: (b) A 95% confidence interval for the proportion with both partners showing their dating partner in their Facebook profile picture is about 0.40 to 0.66 . What is the conclusion in a hypothesis test to see if the proportion is different from 0.5? What significance level is being used? Conclusion: H0 Significance level: 1 Roan, Shari, The true meaning of Facebooks in a relationship’, Los Angeles Times, February 23, 2012, reporting on a study in Cyberpsychology, Behavior, and Social Networking. Chapter 5, Section 1, Exercise 013 Find the specified areas for a normal density. Warning [removed]Dont show me this message again for the assignment Ok Cancel (a) The area below 77 on a N(75,10) distribution Round your answer to three decimal places. area=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% (b) The area above 26 on a N(20,6) distribution Round your answer to three decimal places. area[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% (c) The area between 11 and 14 on a N(12.2, 1.6) distribution Round your answer to three decimal places. area=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% Chapter 5, Section 1, Exercise 020 Find endpoint(s) on the given normal density curve with the given property. Warning [removed]Dont show me this message again for the assignment Ok Cancel (a) The area to the left of the endpoint on a N(5,4) curve is about 0.10. Round your answer to two decimal places. endpoint[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% (b) The area to the right of the endpoint on a N(500,24) curve is about 0.05. Round your answer to the nearest integer. endpoint=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% Chapter 5, Section 1, Exercise 028 Warning [removed]Dont show me this message again for the assignment Ok Cancel Choose the graph for the middle 80% for a standard normal distribution. [removed] [removed] [removed] [removed] [removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel Choose the graph for the the middle 80% for a standard normal distribution converted to a N(100,15) distribution. [removed] [removed] [removed] [removed] [removed] Chapter 5, Section 1, Exercise 031 Random Samples of College Degree Proportions The distribution of sample proportions of US adults with a college degree for random samples of size n=500 is N(0.275,0.02). How often will such samples have a proportion, Ùp, that is more than 0.300? Round your answer to one decimal place. [removed]% of samples of 500 US adults will contain more than 30.0% with at least a bachelors degree. Warning [removed]Dont show me this message again for the assignment Ok Cancel the absolute tolerance is +/-0.1 Chapter 5, Section 1, Exercise 040 Curving Grades on an Exam A statistics instructor designed an exam so that the grades would be roughly normally distributed with mean m=75 and standard deviation ?=11. Unfortunately, a fire alarm with ten minutes to go in the exam made it difficult for some students to finish. When the instructor graded the exams, he found they were roughly normally distributed, but the mean grade was 60 and the standard deviation was 18. To be fair, he decides to curve the scores to match the desired N(75,11) distribution. To do this, he standardizes the actual scores to z-scores using the N(60,18) distribution and then unstandardizes those z-scores to shift to N(75,11). What is the new grade assigned for a student whose original score was 45? Round your answer to the nearest integer. new score=[removed] How about a student who originally scores an 87? Round your answer to the nearest integer. new score[removed] Chapter 5, Section 2, Exercise 044 Find the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately normally distributed. A 95% confidence interval for a proportion p if the sample has n=200 with Ùp=0.34, and the standard error is SE=0.03 Round your answers to three decimal places. The 95% confidence interval is[removed]to[removed]. Chapter 5, Section 2, Exercise 046 Find the indicated confidence interval. Assume the standard error comes from a bootstrap distribution that is approximately normally distributed. A 90% confidence interval for a mean mif the sample has n=80 with `x=22.9 and s=5.8, and the standard error is SE=0.65 Round your answers to three decimal places. The 90% confidence interval is[removed]to[removed]. Chapter 5, Section 2, Exercise 059 Where Is the Best Seat on the Plane? A survey of 1000 air travelers1 found that 60% prefer a window seat. The sample size is large enough to use the normal distribution, and a bootstrap distribution shows that the standard error is SE=0.015. Use a normal distribution to find a 90% confidence interval for the proportion of air travelers who prefer a window seat. Round your answers to three decimal places. The 90% confidence interval is[removed]to[removed]. 1Willingham, A., And the best seat on a plane is 6A!, HLNtv.com, April 25, 2012. Warning [removed]Dont show me this message again for the assignment Ok Cancel Chapter 5, Section 2, Exercise 061 Smoke-Free Legislation and Asthma Hospital admissions for asthma in children younger than 15 years was studied1 in Scotland both before and after comprehensive smoke-free legislation was passed in March 2006. Monthly records were kept of the annualized percent change in asthma admissions, both before and after the legislation was passed. For the sample studied, before the legislation, admissions for asthma were increasing at a mean rate of 5.2% per year. The standard error for this estimate is 0.7% per year. After the legislation, admissions were decreasing at a mean rate of 18.2% per year, with a standard error for this mean of 1.79%. In both cases, the sample size is large enough to use a normal distribution. 1Mackay, D., et. al., Smoke-free Legislation and Hospitalizations for Childhood Asthma, The New England Journal of Medicine, September 16, 2010; 363(12):1139-45. Warning [removed]Dont show me this message again for the assignment Ok Cancel (a) Find a 95% confidence interval for the mean annual percent rate of change in childhood asthma hospital admissions in Scotland before the smoke-free legislation. Round your answers to one decimal place. The 95% confidence interval is[removed]to[removed]. Warning [removed]Dont show me this message again for the assignment Ok Cancel (b) Find a 95% confidence interval for the same quantity after the legislation. Round your answers to one decimal place. The 95% confidence interval is[removed]to[removed]. Warning [removed]Dont show me this message again for the assignment Ok Cancel (c) Is this an experiment or an observational study? [removed] Experiment [removed] Observational study Warning [removed]Dont show me this message again for the assignment Ok Cancel (d) The evidence is quite compelling. Can we conclude cause and effect? [removed] Yes [removed] No Chapter 5, Section 2, Exercise 064 Penalty Shots in World Cup Soccer A study1 of 138 penalty shots in World Cup Finals games between 1982 and 1994 found that the goalkeeper correctly guessed the direction of the kick only 41% of the time. The article notes that this is slightly worse than random chance. We use these data as a sample of all World Cup penalty shots ever. Test at a 5% significance level to see whether there is evidence that the percent guessed correctly is less than 50%. The sample size is large enough to use the normal distribution. The standard error from a randomization distribution under the null hypothesis is SE=0.043. 1St.John, A., Physics of a World Cup Penalty-Kick Shootout 2010 World Cup Penalty Kicks, Popular Mechanics, June 14, 2010. Warning [removed]Dont show me this message again for the assignment Ok Cancel State the null and alternative hypotheses. What is the test statistic? Round your answer to two decimal places. z=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% What is the p-value? Round your answer to three decimal places. p-value=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% What is the conclusion? [removed] Reject H0 and find evidence that the proportion guessed correctly is not less than half. [removed] Reject H0 and find evidence that the proportion guessed correctly is less than half. [removed] Do not reject H0 and do not find evidence that the proportion guessed correctly is less than half. [removed] Do not reject H0and find evidence that the proportion guessed correctly is less than half. Chapter 5, Section 2, Exercise 065 How Often Do You Use Cash? In a survey1 of 1000 American adults conducted in April 2012, 43% reported having gone through an entire week without paying for anything in cash. Test to see if this sample provides evidence that the proportion of all American adults going a week without paying cash is greater than 40%. Use the fact that a randomization distribution is approximately normally distributed with a standard error of SE=0.016. Show all details of the test and use a 5% significance level. 143% Have Gone Through a Week Without Paying Cash, Rasmussen Reports, April 11, 2011. Warning [removed]Dont show me this message again for the assignment Ok Cancel State the null and alternative hypotheses. What is the test statistic? Round your answer to two decimal places. z=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% What is the p-value? Round your answer to two decimal places. p-value=[removed] Warning [removed]Dont show me this message again for the assignment Ok Cancel the tolerance is +/-2% What is the conclusion? [removed] Do not reject H0 and find evidence that the proportion is greater than 40%. [removed] Do not reject H0 and do not find evidence that the proportion is greater than 40%. [removed] Reject H0 and find evidence that the proportion is not greater than 40%. [removed] Reject H0 and find evidence that the proportion is greater than 40%. Warning [removed]Dont show me this message again for the assignment Ok Cancel question.docx 5 years ago Report Issue (A) THE EVIDENCE AGAINST THE NULL HYPOTHESIS IS SIGNIFICANT, BUT ONLY AT THE 10% LEVEL. 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